4x^2+10/2=5

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Solution for 4x^2+10/2=5 equation:



4x^2+10/2=5
We move all terms to the left:
4x^2+10/2-(5)=0
determiningTheFunctionDomain 4x^2-5+10/2=0
We add all the numbers together, and all the variables
4x^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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